[7(b+5)-17]+[2(b+2)+5]=

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Solution for [7(b+5)-17]+[2(b+2)+5]= equation:


Simplifying
[7(b + 5) + -17] + [2(b + 2) + 5] = 0

Reorder the terms:
[7(5 + b) + -17] + [2(b + 2) + 5] = 0
[(5 * 7 + b * 7) + -17] + [2(b + 2) + 5] = 0
[(35 + 7b) + -17] + [2(b + 2) + 5] = 0

Reorder the terms:
[35 + -17 + 7b] + [2(b + 2) + 5] = 0

Combine like terms: 35 + -17 = 18
[18 + 7b] + [2(b + 2) + 5] = 0

Remove brackets around [18 + 7b]
18 + 7b + [2(b + 2) + 5] = 0

Reorder the terms:
18 + 7b + [2(2 + b) + 5] = 0
18 + 7b + [(2 * 2 + b * 2) + 5] = 0
18 + 7b + [(4 + 2b) + 5] = 0

Reorder the terms:
18 + 7b + [4 + 5 + 2b] = 0

Combine like terms: 4 + 5 = 9
18 + 7b + [9 + 2b] = 0

Remove brackets around [9 + 2b]
18 + 7b + 9 + 2b = 0

Reorder the terms:
18 + 9 + 7b + 2b = 0

Combine like terms: 18 + 9 = 27
27 + 7b + 2b = 0

Combine like terms: 7b + 2b = 9b
27 + 9b = 0

Solving
27 + 9b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-27' to each side of the equation.
27 + -27 + 9b = 0 + -27

Combine like terms: 27 + -27 = 0
0 + 9b = 0 + -27
9b = 0 + -27

Combine like terms: 0 + -27 = -27
9b = -27

Divide each side by '9'.
b = -3

Simplifying
b = -3

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